Elliptic Curve Cryptography

Summary

This documentary gives a brief introduction into elliptic curve cryptography

Elliptic Curve Cryptography

Elliptic curve cryptography is a part of asymmetric cryptography, it is based on the mathematical hard problem to find a solution for the elliptic curve discrete logarithm. The calculations are performed on the algebraic structure of elliptic curves over finite fields, which means we compute points on a elliptic curve over finite field by applying the group operations double and add.

The scalar multiplication of a point on an elliptic curve over a finite field is equivalent to the exponentation of a number in a prime field, therefore the inversion is also called discrete logarithm.

First proposed application of elliptic curves in cryptography was random number generations, now ECC is widely used for key establishment and digital signature schemes.

Simple Weierstrass Elliptic Curve Presentation

• Simple Weierstrass form curve equation:

TODO need to install math extension: https://www.mediawiki.org/wiki/Extension:Math/advancedSettings#Installing_texvc Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y² = x³ + ax + b} The elliptic curve are all points in the x,y coordinates which fulfill the cubic curve equation, whereas a and b are called the characteristic of the curve. The curve needs to be smooth, which means that it will not contain any singularities such as a cusp or a self intersection,

This can be also described by the term: $4a^{3}+27b^{2}\neq 0$

Another characteristic we need to introduce is the point at infinity denoted by 0 (also known as ideal point), which can be thought as identity element infinitly raised on the y axis. Therefore our points on the elliptic curve over R² all fulfill this equation Failed to parse (syntax error): {\displaystyle \{(x,y)∈R2 | y2=x3+ax+b, 4a3+27b2≠0\} \cup \{0\}} and can be presented by:

A point consists of 2 values P(x,y).

Group operations on elliptic curves

According to the group law all points support following operations:

• Point addition: $P+Q=R$
• Point doubling: Failed to parse (unknown function "\math"): {\displaystyle P=Q - 2P=R<\math TODO:Need to install link target extension: https://www.mediawiki.org/wiki/Extension:LinkTarget Test: <span target="_blank">https://cdn.rawgit.com/andreacorbellini/ecc/920b29a/interactive/reals-add.html</span> <div class="toccolours mw-collapsible mw-collapsed " style="width:800px; overflow:auto;"> <div style="font-weight:bold;line-height:1.6;">Geometric derivation of the point addition by the Tangent Chord Law</div> <div class="mw-collapsible-content"> [[File:Ecc_addition.png]] TODO: Need to install Cite extension: https://www.mediawiki.org/wiki/Extension:Cite <ref name="HMV">Hankerson, D., A. Menezes and S. Vanstome: Guide to Elliptic Curve Cryptographie. Springer Verlag New York, Inc., 1. Auflage, 2004.</ref> Given the elliptic curve <math>E:y^2=x^3+ax+b} and the points $P=(x_{1},y_{1})$ and $Q=(x_{2},y_{2})$, we can caculate the coordinates of the point $R=P+Q=(x_{3},y_{3})$ as follows.

1. Calculation of $y_{3}$

• We know the equation from the line

$y=kx+d\qquad {\text{concising of}}\qquad k={\frac {\Delta y}{\Delta x}}$

• Therfore

$k={\frac {y_{2}-y_{1}}{x_{2}-x_{1}}}$ and we can find the intersection with the y-axis and achieve d $d=y_{1}-kx_{1}={\frac {y_{1}\cdot x_{2}-y_{1}\cdot x_{1}-y_{2}\cdot x_{1}+y_{1}\cdot x_{1}}{x_{2}-x_{1}}}={\frac {y_{1}\cdot x_{2}-y_{2}\cdot x_{1}}{x_{2}-x_{1}}}$.

• $y_{3}$ we can find by insertion in the line equation:

$y_{3}=(-1){\bigg (}{\frac {y_{2}-y_{1}}{x_{2}-x_{1}}}\cdot x_{3}+y_{1}-{\frac {y_{2}-y_{1}}{x_{2}-x_{1}}}\cdot x_{1}{\bigg )}={\bigg (}{\frac {y_{2}-y_{1}}{x_{2}-x_{1}}}{\bigg )}(x_{1}-x_{3})-y_{1}$

2. Calculation of $x_{3}$

• Now we insert the values of the line equation into the elliptic curve equation:

${\begin{aligned}(k\cdot x+d)^{2}&=x^{3}+a\cdot x+b\\k^{2}x^{2}+2k\cdot x\cdot d+d^{2}&=x^{3}+a\cdot x+b\\x^{3}-x^{2}k^{2}+x(a-2k\cdot d)+b-d^{2}&=0\end{aligned}}$

• The cross points can be searched by

${\begin{aligned}(x-x_{1})\cdot (x-x_{2})\cdot (x-x_{3})&=0\\(x^{2}-x\cdot x_{2}-x\cdot x_{1}+x_{1}\cdot x_{2})\cdot (x-x_{3})&=0\\x^{3}-x^{2}\cdot x_{2}-x^{2}\cdot x_{1}+x\cdot x_{1}x_{2}-x^{2}\cdot x_{3}+x\cdot x_{2}x_{3}+x\cdot x_{1}x_{3}-x_{1}x_{2}x_{3}&=0\\x^{3}-x^{2}(x_{1}+x_{2}+x_{3})+x(x_{1}x_{2}+x_{2}x_{3}+x_{1}x_{3})+x_{1}x_{2}x_{3}&=0\end{aligned}}$

• Now we can conclude from the second term

${\begin{aligned}x^{3}-x^{2}{\underline {k^{2}}}+x(a-2k\cdot d)+b-d^{2}&=0\\x^{3}-x^{2}{\underline {(x_{1}+x_{2}+x_{3})}}+x(x_{1}x_{2}+x_{2}x_{3}+x_{1}x_{3})+x_{1}x_{2}x_{3}&=0\\k^{2}&=x_{1}+x_{2}+x_{3}\end{aligned}}$

• and achieve a solution for $x_{3}$ by:

$x_{3}=k^{2}-x_{1}-x_{2}={\bigg (}{\frac {y_{2}-y_{1}}{x_{2}-x_{1}}}{\bigg )}^{2}-x_{1}-x_{2}$

Algebraic group of points

The points further comply associative and commutative algebraic group laws and the handling of the neutral element:

• • closure: Failed to parse (unknown function "\math"): {\displaystyle P+Q=R \forall P,Q,R \in E<\math>b ** associative: <math>P+0=0+P \forall P \in E<\math> ** identity element and inverse that: <math>P+(-P) = 0 \forall P \in E<\math> ** cummutative: <math>P+(Q+R)=(P+Q)+R \forall P,Q,R \in E<\math> The inverse point of a point P(x,y) is therfore P(x,-y). == Scalar Multiplication == === Double and Add algorithm === === Calculation in projective coordinates === === Side Channel Attacks === === Montgomery ladder === == Standardization of elliptic curves == == Curve25519== Curve25519 is a highly optimized curve proposed by Daniel J. Bernstein (djb) in 2005. The curve equation is <math>y^2=x^3+486662x^2+x<\math> over a prime field <math>2^{255}-19}